Physics, asked by sumitgoswami9077, 1 year ago

A particle has an initial velocity of 3i^+4j^ and an acceleration of 0.4i^+0.3j^.Its speed after 10s is:

Answers

Answered by shivam8899
21
v = u + at
v = 3i^+4j^ + (0.4i^+0.3j^)10
v = 
3i^+4j^ + 4i^ + 4j^
v = 7i^ + 7j^
when we take resultant of this
v = 7√2 m/s

i hope it will help you
regards
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