Physics, asked by jaindrasingh5078, 1 year ago

A particle has an initial velocity of 3i^+4j^ and an acceleration of 0.4i^+0.3j^. Its speed after 10 sec is

Answers

Answered by TheInterpelled
0

\mathfrak{The\:Answer\:is}

Speed = 3i^+4j^ - 0.4i^+0.3j^ * 10

= 7 m/s

\boxed{Hope\:This\:Helps}

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