A particle has an initial velocity of
4 +3; and an acceleration of
0.4i + 0.3j. Its speed after 10 s is
(A) 10 units
(B) 7 units
(C) 7V2 units
(D) 8.5 units
Answers
Answered by
1
Answer:
v= u+ a t
v=(3
i^+4
j^)+10(0.4
i^ +0.3j)
v =7 i
^ +7 j^
∣ v ∣=7 2
Explanation:
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