Question

a particle has been projected from origin with a speed of 20m/s at an angle 60 with horizontal.the horizontal direction as y.the x coprdinate of the particle when its velocity vector becomes perpendicular to the initial velocity vector is​

Answer 1

Explanation:

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11th

Physics

Motion in a Plane

Projectile Motion

A ball is projected with a ...

PHYSICS

A ball is projected with a velocity 20

3

m/s at angle 60

o

to the horizontal. The time interval after which the velocity vector will make an angle 30

o

to the horizontal is (in seconds)

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ANSWER

Given : u=20

3

m/s θ=60

o

Horizontal component of velocity initially u

x

=u cos60=20

3

×

2

1

=10

3

m/s

Since, there is no acceleration in horizontal direction. So horizontal component of velocity remains the same all the time.

Final horizontal component of velocity v

x

=u

x

=10

3

m/s

Final velocity makes an angle 30

o

with horizontal.

So, vertical component of final velocity v

y

=u

x

tan30=10

3

×

3

1

=10

Initial vertical comonent of velocity u

y

=usin60=20

3

×

2

3

=30 m/s

Using v

y

=u

y

−gt

∴ 10=30−10t

⟹ t=2 s

Answer 2

Answer:

Abv ans is crrct ......