A particle has displacement of 12m toward the east ans the 5m towards north then 6m vertically upwards the sum of these displacement is give me solutions
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tet us first calculate the displacement for 12m and 5m.
R1=√(12^2 +5^2)
= √(169)
= 13m
Now calculate for R1 and 6m vertically upward.
R2=√(13^2 + 6^2)
=√(205)
=14.32m
so resultant displacement is 14.32m
i hope it will help you
regards
R1=√(12^2 +5^2)
= √(169)
= 13m
Now calculate for R1 and 6m vertically upward.
R2=√(13^2 + 6^2)
=√(205)
=14.32m
so resultant displacement is 14.32m
i hope it will help you
regards
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