Question

A particle has initial velocity (21 +33) and
acceleration (0.31 +0.2]). The magnitude of
velocity after 10 s will be (AIPMT (Prelims)-2012]
(2) 9 units
(1) 5 units
(3) 9/2 units
(aX 512 units
ANSWER PLS WITH EXPLAINATION​

Answer 1

Answer:

Velocity after time ′t′=(ux+axt)i+(uy+ayt)j 

⇒a=[2+0.3(10)]i+[3+0.2(10)]j=5i+5j

So, The magnitude of velocity after 10 seconds will be 

∣a∣=52+52=52 units.