Question

A particle has initial velocity 2i + 3 j and acceleration 0.3 i + 0.2 j the magnitude of velocity after 10 seconds will be

Answer 1

Answer:

The magnitude of velocity after 10 seconds is $5\sqrt{2}\ units$.

Explanation:

It is given that,

Initial velocity of the particle, $u = 2 i +3 j$

Acceleration of the particle, $a=0.3i +0.2 j$

Time taken, t = 10 s

We need to find the velocity after 10 seconds. Let it is equal to v. Using first equation of motion as :

$v=u+at$

$v=2 i +3 j+(0.3i +0.2 j)10$

$v=2 i +3 j+(3i +2 j)$

$v=5i+5j$

Magnitude of v, $|v|=\sqrt{5^2+5^2} =5\sqrt{2}\ units$

So, the magnitude of velocity after 10 seconds is $5\sqrt{2}\ units$. Hence, this is the required solution.