A particle has initial velocity 2icap+3jcap and accelaration -3icap +2jcap what is the magnitude of velocity after 10 sec
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Answer:
v= u+ at
Explanation:
u =2î +3j. u=√2²+3²
=√13
a = -3î+2j. u=√-3²+2²
=√13
t=10s
v= √13 + √13*10
=√13(1+10)
=11√13
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