Question

A particle has initial velocity 3i+4j and acceleration 0.4+0.3. Find speed after 10 second?

Answer 1

Answer:

7i+7j

Explanation:

u=3i+4j

a=0.4i+0.3j

t=10s

v=?

v=u+at

=3i+4j+(0.4i+0.3j)10

=3i+4j+4i+3j

v=7i+7j

Answer 2

Answer:

By newtons 1st law of motion

v=u+at

v=3j+4j+(0.4+0.3) ×10

v=7j+7/10×10

v=7j+7

Ok...