Question

a particle has initial velocity 3i+4j and has acceleration 0.4i+0.3j'its speed after 10s is class 11 pls

Answer 1

Answer:

7root2m/s

Explanation:

u=3i+4j

a=0.4i+0.3j

t=10s

v=?

Applying v=u+at,

v=7i+7j

Speed=|v|=root7^2+7^2=7root2

Hope it helps

Answer 2

Answer:

.

.

.

.

v = u + a t

v=(3 i +4 j)+10(0.4 i^ +0.3 j^v =7 i

^

+7

j

^

∣ v ∣=7 /2