Question

A particle has initial velocity equal to (3i+8) m/s. If it
has a constant acceleration a = (21 +2j) m/s2, then its
velocity at time t = 3 s will be​

Answer 1

Answer:

(3i + 6j + 71) m/s

Explanation:

Given:

Initial velocity (u) = (3i + 8) m/s

Acceleration (a) = (21 + 2j) m/s²

Time (t) = 3 seconds

To find:

Final velocity (v)

Formula:

v = u + at

⇒ v = (3i+8) + 3(21+2j)

⇒ v = 3i + 8 + 63 + 6j

⇒ v = (3i + 6j + 71) m/s

Hence, the velocity of the particle at 3 seconds will be (3i + 6j + 71) m/s.