A particle has initial velocity equal to (3i+8) m/s. If it
has a constant acceleration a = (21 +2j) m/s2, then its
velocity at time t = 3 s will be
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Answer:
(3i + 6j + 71) m/s
Explanation:
Given:
Initial velocity (u) = (3i + 8) m/s
Acceleration (a) = (21 + 2j) m/s²
Time (t) = 3 seconds
To find:
Final velocity (v)
Formula:
v = u + at
⇒ v = (3i+8) + 3(21+2j)
⇒ v = 3i + 8 + 63 + 6j
⇒ v = (3i + 6j + 71) m/s
Hence, the velocity of the particle at 3 seconds will be (3i + 6j + 71) m/s.
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