Question

A particle has initial velocity to 2i + 3 J and acceleration 0.3 i + 0.20j the magnitude of velocity after 10 second will be​

Answer 1

Answer:

$2 \times \sqrt{13}$

Step-by-step explanation:

|u|=/4+9=/13

|a|=/0.13=/13/10

so,v=u+at

we get |v|=2/13