Question

a particle has the same range for two angles of projection with the same speed 10 m/s. the corresponding maximum height attained by particle is h1 and h2 respectively.then ​

Answer 1

Answer:

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Answer 2

Answer:

For same range angle of projection will be θ&90−θ

For same range angle of projection will be θ&90−θ

R=

g

u

2

2sinθcosθ

h

1

=

g

u

2

sin

2

θ

h

2

=

g

u

2

sin

2

(90−θ)

h

1

h

2

R

2

=16R=

g

u

2

2sinθcosθ

h

1

=

g

u

2

sin

2

θ

h

2

=

g

u

2

sin

2

(90−θ)

h

1

h

2

R

2

=16