Question

A particle has the same range for two different angle of projection. If H1 & H2 are the maximum height attained by the projectile and R is the range then find the relation between H1,H2 & R​

Answer 1

Explanation:

ANSWER

h

1

=

2g

u

2

sin

2

θ

h

2

=

2g

u

2

sin

2

(90−θ)

,R=

g

u

2

sin2θ

Range R is same for angle θ and (90−θ)

∴h

1

h

2

=

2g

u

2

sin

2

θ

×

2g

u

2

sin

2

(90−θ)

=

4g

2

u

4

(sin

2

θ)×sin

2

(90=θ)

=

4g

2

u

4

(sin

2

θ)×cos

2

θ

4g

2

u

4

(sinθcosθ)

2

=

16g

2

u

4

(sin2θ)

2

16g

2

(u

2

sin2θ)

2

=

16

R

2

or R

2

=16 h

1

h

2

orR=4

h

1

h

2