Physics, asked by 4w3s0m3, 2 months ago

A particle has velocity (5 m/s)i - (4 m/s)j. During a time period of 1.2 s, its velocity changes to (1.5 m/s)i + (6 m/s)j. Determine the magnitude of acceleration of the object.

Answers

Answered by shibumonshibumon123
0

Explanation:

consider as two separate case, ie, velocity and acceleration in x and y.

here u=intial velocity

v= final velocity

suffix x and y shows direction in x and y respectively

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