Question

a particle having 5 micro coulomb charge is taken from a potential of 40 volt to a potential of 120 volt calculate the work done​

Answer 1

Explanation:

5 microcoulomb charge=0.000005coulomb 5×10^-6coulomb

v=40v

workdone=VQ

40×5×10^-6

200×10^-6

2×10^-4 J

and when Vis increased

V=120V

then work=120×5×10^-6

600×10^-6

6×10^-4J

work = 6-2×10^-4

=4×10^-4J

Hope it helps.......