Question

A particle having a charge 10 ug and mass 1 ug moves in a horizontal circle of radius 10cm under the influence of a magnetic field of 0.1 T. When the particle is at P, a uniform electric field is switched on so that the particle starts moving along the tangent with uniform velocity.The electric field is .

(1). 0.1 V/m
(2). 1.0 V/m
(3). 10.0 V/m
(4). 100 V/m





plz give me solution​

Answer 1

Answer:(3)

q=10μc=10x10^(-6)C

m=1μg=10^(-6)x10^(-3)kg

r=10^(-1)m

b=10^(-1)T

Velocity; V=bqr/m

                 =(10^-1 ) (10^-1) (10x10^-6)/1 x 10^-6 x10^-3

                 =10^-1 x 10^3

               V=100m/s

V= E/B

E= B x V

E= 0.1 x 100

E= 10 v/m