Question

A particle having a charge of 10 micro columb and a mass of 1 microgram moves in a horizontal circle of radius 10cm under the influence of a magnetic field 0.1t. when the particle is at a point p a uniform electric field is switched on so that the particle starts moving along the tangent with uniform velocity. find the electric field

Answer 1

answer : 10 N/C

explanation : charge on particle, q = 10μC = 10 × 10^-6C = 10^-5 C

mass of particle, m = 1μg = 10^-9 kg

magnetic field , B = 0.1T

so, magnetic force acting on particle, F = q(v × B) = qvBsinθ

= 10^-5 × v × 0.1T × sin90°

= 10^-6 × v .......(1)

radius of circle, r = mv/qB

so, v = qBr/m ......(2)

from equations (1) and (2),

F = 10^-6 × {10^-5C × 0.1T × 0.1m/10^-9kg}

= 10^-4 N

now, force due to electric field, F = qE

so, 10^-4 = 10^-5 × E

or, E = 10 N/C

hence, electric field = 10 N/C

Answer 2

Answer:

hope you understand

thank u