A particle having charge q enters a region of uniform magnetic field b
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Answer:particle having charge q enters a region of uniform magnetic field B directed inwards and is deflected as shown to a distance d above the original line of flight as shown. What is the (magnitude of) momentum of the particle?
(A)qBd2(B)qBa2(C)qBa22d(D)qB2(d+a2d)
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A)
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The direction of motion of the particle and the direction of the magnetic field are known. Therefore, we can find the direction of the magnetic force acting on a positive and negative charge using Lorent's law.
This question is all about writing radius in an appropriate way
R2=y2+(r−x)2
R2=(x2+y2)2x =PqB
Ans : (d)
The vector product between v and B points upwards in the figure thus indicating that the charge of the particle is positive.
The Force acting on the moving charge F=qvB
As a result of the magnetic force, the charged particle will follow a spherical trajectory. The centripetal force Fc=mv2r
Now, the Force acting on the moving charge F=Fc, the centripetal force →qvB=mv2r
⇒r=mvqB=pqB, where p is the momentum of the particle.
Explanation: