Question

a particle having charge q1 exerts F electrostatic force on charge q2 at rest. If a particle having charge q1/4 is placed midway b/w the line joining the two charges q1 and q2. Then electrostatic force on q2 due to q1 will become​

Answer 1

Explanation:

the principle of superposition state that, the force exerted by a charge on other charge is independent of other charges . there fore the force on q2 due to q1 is remain same but the net force on q2 due to q1 and q1/4 is changed so, the answer is F

Answer 2

Given:

A particle having charge q1 exerts F electrostatic force on charge q2 at rest. If a particle having charge q1/4 is placed midway b/w the line joining the two charges q1 and q2.

To Find:

Then electrostatic force on q2 due to q1 will become?

Solution:

here, it is given that, a particle having charge q1 exerts F electrostatic force on charge particle q2 at rest.

therefore,

$F=\dfrac{Kq1q2}{r^2}$

also, given that, a particle having charge q1/4 is placed midway between the line joining the two charges q1 and q2. Then we have to find the electrostatic force on q2 due to q1 ??

since, we know that ;

The principal of superposition of charges states that , the electrostatic force exerted by a charged particle on the other charged particle is independent of the other charges.

therefore, according to principal of superposition of charges, the electrostatic force on charged particle q2 due to charged particle q1 is remains same. But the net forces acting on q2 due to q1 and q1/4 is changed.

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