a particle having initial velocity u is moving with constant acceleration for time t.find the displacement of particle in the last one second
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V =u+at is your answer
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Thanks for your question !
The displacement of a particle in time (t) is given,
s = ut + 1/2at²
Let the time is t - 1, the displacement of a particle is :
S' = u (t-1) + 1/2a (t-1)² - - - (Substituting t-1 as t)
Now, we have secured S and S' value for substituting in equations. Let the equation is to be displacement of particle in one second.
The displacement of particle in last one second is : St = S - S'
= ut+1/2 at²-[u(t-1)+1/2 a(t-1)²]
= ut + 1/2at² - ut + u - 1/2 a(t-1)²
= 1/2at² + u - 1/2 a (t +1-2t)
= 1/2at² + u - 1/2at² - a/2 + at
Hence, the displacement of particle in one second will be S = u + a/2(2t-1)
The displacement of a particle in time (t) is given,
s = ut + 1/2at²
Let the time is t - 1, the displacement of a particle is :
S' = u (t-1) + 1/2a (t-1)² - - - (Substituting t-1 as t)
Now, we have secured S and S' value for substituting in equations. Let the equation is to be displacement of particle in one second.
The displacement of particle in last one second is : St = S - S'
= ut+1/2 at²-[u(t-1)+1/2 a(t-1)²]
= ut + 1/2at² - ut + u - 1/2 a(t-1)²
= 1/2at² + u - 1/2 a (t +1-2t)
= 1/2at² + u - 1/2at² - a/2 + at
Hence, the displacement of particle in one second will be S = u + a/2(2t-1)
Anonymous:
Awesome !!
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