Question

A particle having initial velocity u with constant acceleration a for time T.
(A) find the displacement of the particle in first 2 seconds.
( B) evaluate displacement for u=2 m/s, a=1m/s^2 and time=5 second.​

Answer 1

Solution :-

Given :-

▪️Initial velocity = u

▪️Acceleration for time T = a

(A)

t = 2 sec

◾As we know

$S = ut + \dfrac{1}{2} at^2$

$\implies S = u(2) + \dfrac{1}{2} a \times 2^2$

$\implies S = 2u + 2a$

(B)

◾Now

▪️Initial velocity (u) = 2 m/s

▪️Acceleration (a) = 1 m/s²

▪️Time (t) = 5 sec

◾Now from motion equation ,

$S = ut + \dfrac{1}{2} at^2$

$\implies S = 2\times 5 + \dfrac{1}{2} \times 1 \times 5^2$

$\implies S = 10 + \dfrac{25}{2}$

$\implies S = \dfrac{20 + 25}{2}$

$\implies S = \dfrac{45}{2}$

$\implies S = 22.5$

So displacement = 22.5 m