A particle having mass 2kg is moving along straight line 3x 4y 5
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4y=−3x+5
y=−34x+54
Slope =−34
=tanθ
Angular momentum about the origin
L=mvd
[p×perpendiculardistance]
=2×8×d
=16d
Y=0,x=53
Y=0,x=53
In OCB,
sinθ=OCOB
=dOB
From ΔOAB,tanθ=5/45/3
=34
=> sinθ=35
∴35=d5/3
d=1m
∴L=16kgm2/s
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