A particle having mass m is projected wuth velocity u m/s at an angle theta with horizontal. Find out the torque about point of projection when particle was at
1. maximum height
2. just about to hit the ground
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0
Answer:
=rFsinθ=2Rmg=2gv02sin2θmg
τ=2mv02sin2θ
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1
Answer:
please refer to the attachment above
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