Question

a particle hs initial velocity (3i+4j) and constant acceleration (4i-3j).its speed after one second is

Answer 1

u = 3i + 4j
a = 4i -3j
t = 1
a = (v-u)/t
4i -3j = v - 3i - 4j
v = 4i + 3i -3j + 4j
v = 7i + j