A particle in a circular motion with acceleration alpha=0.2rad/s at t=5s,then the angular displacement is
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1.23 this are the answer
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Given that Angular acceleration of the particle = α=0.2rad/s
2
Using Ist equation of motion for circular motion we get
ω=ω
0
+αt
Since particle is at rest initially ∴ω
0
=0
⟹ω=αt=0.2×10=2rad/
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