Question

A particle in a cone-shaped cap lying on the ground travels in a circular path at a speed of 0.2 ms ^ -1. If the height of the cap is 10 cm and the pointed part is facing upwards, what will be the height of the particle from the ground?​

Answer 1

Answer:

Rsin θ=mg

and, Rsin θ=mv

2

/r

⟹tan θ=gr/v

2

=r/h

⟹v=

gh

=

10×0.1

=1m/s

Explanation:

Thank you

Answer 2

N cos theta = mv²/r - - 1

N sin theta = mg - - 2

2÷1, Tan theta = gr/v² = r/h

v = root ( gh) => (0.2)² = 10× h

h = 0.04/ 10 = 0.004 m or 0.4 cm