Question

A particle in a generator is accelerated from rest at the rate of 55 metre per second squared.what is the velocity at t=3s?​

Answer 1

Given :

▪ Initial velocity of particle = zero

▪ Acceleration of particle = 55m/s$^2$

To Find :

Velocity of particle at t = 3s

Concept :

→ Acceleration is defined as ratio of change in velocity to the time interval.

→ Acceleration is a vector quantity.

→ Acceleration can be positive, negative and zero.

Calculation :

$\implies\bf\:a=\dfrac{\Delta{velocity}}{\Delta{time}}=\dfrac{v-u}{t}\\ \\ \implies\sf\:55=\dfrac{v-0}{3}\\ \\ \implies\sf\:v=55\times 3\\ \\ \implies\boxed{\bf{\purple{a=165\:mps}}}$