a particle in motion and connected to a string is just able to complete a vertical circle of radius R acceleration of the particle when its velocity becomes vertical is
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The minimum velocity to the lowest point of a particle is completely circle. So the tendency which becomes is maximum to the topmost circle.
At the top, tension is given by T = mvT2/R - mg, where vT = speed of the particle at the top.
=> mvT2/R = T + mg
For vT to be minimum, T ≈ 0 => vT = √gR
If vB be the critical velocity of the particle at the bottom, then from conservation of energy
Mg(2R) + 1/2 mvT2 = 0 + 1/2 mvB2
As vT = √gR => 2mgR + 1/2 mgR = 1/2 mvB2
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Answer:10root10 m/s^2
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