Question

A particle in moving in a circular path of radius 7m with speed.it completes one revolution in 4sec .find the speed of the particle?​

Answer 1

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Speed=11\:m/s}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline \bold{Given :}} \\ \tt: \implies Radius \: of \: circular \: path(r)= 7 \: m \\ \\ \tt: \implies Time \: taken(t) = 4 \: sec \\ \\ \red{\underline \bold{To \: Find :}} \\ \tt: \implies Speed \: of \: particle = ?$

• According to given question :

$\bold{As \: we \: know \: that} \\ \tt: \implies Circumference \: of \: path = 2\pi r \\ \\ \tt: \implies Circumference \: of \: path = 2 \times \frac{22}{7} \times 7 \\ \\ \green{\tt: \implies Circumference \: of \: path = 44 \: m} \\ \\ \bold{For \: speed : } \\ \tt: \implies Speed = \frac{Distance}{Time} \\ \\ \tt: \implies Speed = \frac{44}{4} \\ \\ \green{\tt: \implies Speed =11 \: m/s} \\ \\ \blue{ \bold{Some \: related \: formula}} \\ \orange{ \tt \circ \: {v}^{2} = {u}^{2} + 2as} \\ \\ \orange{ \tt \circ \: s = ut + \frac{1}{2} {at}^{2} } \\ \\ \orange{ \tt \circ \: v = u + at}$

Answer 2

$\huge\sf{Answer:}$

☆ According to the question:

⇏ A particle in moving in a circular path of radius 7 m with speed.it completes one revolution in 4 seconds.

☆ To find:

⇏ Find what is the speed of the particle?

☆ Using formula:

Circumference formula: 2πr

⇏ $\sf2\pi r = 2 \times \dfrac{22}{7} \times 7$

⇏ ${\sf{\boxed{\sf{44}}}}$

Therefore, 43 is the circumference of path.

☆ Finding the speed of the particle:

Using speed formula:

⇏ $\sf Speed = \dfrac{Discovered \: covered}{Time}$

⇏ $\sf Speed = \dfrac{44}{4}$

⇏ ${\sf{\boxed{\sf{11}}}}$

Therefore, 11 m/s is the speed of the particle.