Question

a particle in S.H.M. has period 1 second and amplitude 5 cm. find acceleration when it is at 2 cm from it's mean position​

Answer 1

Answer:

a=-8pi^2

Explanation:

T=1sec

A=5cm

Now

a=-omega^2 x

So a=-(2*pi/T)^2 *x

= - 4pi^2*2

= - 8pi^2