Question

A particle in SHM has displacement x given by x is equal to 3 cos(5πt+π) where x is the metre and t is in second. where is the particle at t=0 and t=1/2s?​

Answer 1

Answer:

x=5sinπt+12sin(πt+π/2)

=5sinπt+12cosπt

=13sin(πt+θ) where cosθ=5/12

Amplitude, A=max(x)=13 cm

Time period, T=2π/ω=2π/π=2 s

Initial phase, α=∠(x)

t=0

=θ

α=cos

−1

(5/12)