a particle initially at rest is accelerated by force 20N for 15 seconds .After that it undergoes collision with a wall normally and sticks to it. The collision happened 0.1sec.What will be force exerted by particle on wall ?
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A particle initially at rest is accelerated by force 20N for 15 seconds .After that it undergoes collision with a wall normally and sticks to it. The collision happened 0.1sec.
Explanation:
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Answer - 3000N
Explanation:
About the particle we have
u = 0m/s
Force =15 N
Acceleration =v-u/t
u=0m/s
Therefore,
Acceleration (a) =v/t
F=m*a
20=m*v/15
Therefore, m*v =300---------eqn1
Momentum (P) =300 kg.m/s
By the law of conservation of momentum.
Force exerted by particle on wall =mass * acceleration
Using eqn 1
Force = 300/0.1
=3000 Newton.
Hence, force exerted on wall is 3000N.
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