Question

A particle initially at rest, moves with an
acceleration 5 m s-2 for 5 s. Find the distance
travelled in (a) 4 s, (b) 5 s and (c) 5th second.​

Answer 1

Answer:

u=0

a=5 ms

−2

As it undergoes acceleration for 5 s, the distance travelled in 4 s is due to an accelerated motion.

t=4 s

∴s=ut+

2

1

at

2

=(0×4)+(

2

1

×5×4

2

)=40 m