Question

A particle initially at rest, moves with an acceleration of 5m/s2for 2s. Find the distancet ravelled by the particle.

Answer 1

Answer:Distance traveled in 5th second = Distance traveled in 5 s− Distance traveled in 4 s

Using s=ut+(1/2)at  

2

 

Distance traveled in 5 s =(1/2)×5×5  

2

 

                                         =62.5 m

Distance traveled in 4 s =(1/2)×5×4  

2

 

                                         =40 m

Distance traveled in 5th s =(1/2)×5×5  

2

 

                                            =62.5 m=S  

2

​  

−S  

1

​  

=(62.5−40)m=22.5m

Explanation:

Answer 2

Answer:10m

Explanation:

given

u=0

a=5

t=2s

by applying 2nd equation of motion

s=ut+1/2at^2

s=0*t+1/2at^2

s=5*2*2*1/2

s=10m