Question

A particle initially at rest moving along x axis with an acceleration that varies with time as a=( 60t + 5) metre per second square if start from origin what is the covered in one second​

Answer 1

Answer:

u=0(as body started from Rest )

at time=1

acceleration become=60*1+=65m/s^2

we know that

s=ut+1*a*t^2/2

where s=distance covered by body

u=initial velocity

a=acceleration

t=time

s=0+65*1=65m

body covered 65 m in 1s when it accelerate from a=60t+5

Answer 2

from 1 eq of motion

as v=u+at

v=? u=0(given , initially at rest) a=60t+5 t=1

then v=0 + 60t + 5

v= 60t+5