Question

A particle initially at rest starts moving with a uniform acceleration then ratio of the distance covered by it in the first second and the first 3 seconds isf

Answer 1

Answer:

1:9

Explanation:

using the second equation of motion

s=ut+1/2at^2

s=displacement(distance) covered

u=initial velocity

a=acceleration

t=time

u=0,

1st second

s=1/2at^2, therefore s=1/2a(1^2)= 1/2a............(i)

3rd second, s=1/2a(3^2)= 9/2a.........................(ii)

dividing equation (i) with (i1)

we get 1/9

hence the ration of 1st distance to 3rd =1:9