Question

A particle initially at rest travels a distance 80 m in 4 s with a constant acceleration. Calculate its acceleration and final velocity at the end of 4s​

Answer 1

Answer:

the answer is 10m/s^2 and 40m/sec

Explanation:

Initial velocity =u= 0 m/sec

final velocity =v = ?

distance =s= 80m

time = 4s

using 2nd equation of motion-

s= ut+1/2at^2

80=0×4+1/2a(4)^2

80= 0+ 1/2a × 16

80= 8a

a= 80/8= 10m/s^2

Now, using 1st equation of motion

v= u+ at

v= 0 + (10)(4)

v= 40 m/ sec