A particle initially at rwst moves witg an acceleration of 5m/s sq for 5 sec. Fing tge distance travelled in 4 sec, 5 sec, 5 ty sec
Answers
Answered by
1
u=0
a=5
in first case
t=4s
s=ut+1/2at^2
s=0×4+1/2×5×4^2
s=0+1/2×5×16
s=0+40
s=40m
in second case
t=5s
s=ut+1/2at^2
s=0+1/2×5×5^2
s= 0+ 1/2×5×25
s=2.5×25
s=62.5m
this is the answer
a=5
in first case
t=4s
s=ut+1/2at^2
s=0×4+1/2×5×4^2
s=0+1/2×5×16
s=0+40
s=40m
in second case
t=5s
s=ut+1/2at^2
s=0+1/2×5×5^2
s= 0+ 1/2×5×25
s=2.5×25
s=62.5m
this is the answer
Harshitasood:
if my answer help u plz mark it as brai liest
Similar questions