Question

a particle is accelerated uniformly from rest, so that after 10 seconds it has achieved a speed of 15m/s. find its acceleration and the distance it has covered.​

Answer 1

Answer:

given initial velocity is zero,and final velocity is 15m/s

t is 10s

acceleration=v-u/t

a=15-0/10

a=3/2m/s^2

and distance traveled is

velocity=distance/time

distance=v*t

=15*10

=150m/s

Answer 2

The acceleration and the distance it has covered is $1.5\ m/s^2$ and 75 meters respectively.

Explanation:

Initial speed, u = 0

Final speed, v = 15 m/s

Time, t = 10 s

The change in velocity divided by time is called acceleration. It is given by :

$a=\dfrac{v-u}{t}\\\\a=\dfrac{15\ m/s}{10\ s}\\\\a=1.5\ m/s^2$

Now using second equation of motion as :

$d=ut+\dfrac{1}{2}at^2\\\\d=\dfrac{1}{2}\times 1.5\times 10^2\\\\d=75\ m$

So, the acceleration and the distance it has covered is $1.5\ m/s^2$ and 75 meters respectively.

Learn more,

Kinematics

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