Physics, asked by gautam7896101972, 1 year ago

A particle is acted upon by constant F1(2i^-3j^+4k^),F2(-i^+2k^-3k^)is displaced on the point A(2,1,0) to the point B(-3,-4,2)find the total work done?

Answers

Answered by RanjanKumar14
33
Hi , here is your answer !!

simple question !!!

A= ( 2,1,0)
B = ( -3 , -4 ,2)


B -A { why ? :- because we have to get change in displacement }


so , B - A => (-5 , -5 ,2 )


now , force => f2-f1



so , F = (-3i^ , 5k^ , 0 )

now , work done = F. S


so , FS = 15 -25 + 0

= -10 j


hence , net work done = is -10 j


hope it help you !!!

thanks !!


gautam7896101972: Thank you
Answered by TheKnowledge
12
Hi , here is your answer !!

simple question !!!

A= ( 2,1,0)
B = ( -3 , -4 ,2)


B -A { why ? :- because we have to get change in displacement }


so , B - A => (-5 , -5 ,2 )


now , force => f2-f1



so , F = (-3i^ , 5k^ , 0 )

now , work done = F. S


so , FS = 15 -25 + 0

= -10 j


hence , net work done = is -10 j


hope it help you !!!

thanks !!

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