A particle is acted upon by constant forces f1=2i-3j+4k and f2=-i+2j-3k, is displaced from the point a (2,1,0) to the point b (-3,-4,2). find the total work done by these forces.
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Answered by
2
Answer:
Here,
F
1
=4
i
^
+
j
^
−3
k
^
,
F
2
=3
i
^
+
j
^
−
k
^
r
1
=
i
^
+2
j
^
+3
k
^
,
r
2
=5
i
^
+4
j
^
+
k
^
Displacement,
r
=
r
2
−
r
1
=(5
i
^
+4
j
^
+
k
^
)−(
i
^
+2
j
^
+3
k
^
)=4
i
^
+2
j
^
−2
k
^
Work done by the forces,
W=[
F
1
+
F
2
]⋅
r
=[(4
i
^
+
j
^
−3
k
^
)+(3
i
^
+
j
^
−
k
^
)]⋅(4
i
^
+2
j
^
−2
k
^
)
=(7
i
^
+2
j
^
−4
k
^
)⋅(4
i
^
+2
j
^
−2
k
^
)=28+4+8=40 J.
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