Question

A particle is acted upon by constant forces F1 vector equal to 3i vector + 6j vector minus 2 k vector and F2is equal to (2i cap-3jcap+5k cap) and it is displaced from the position R1= icap+2j cap-kcap ) to position r2=5i cap +4j cap+3kcap.the total work done by forces is
please please please answer my question..I will follow u​

Answer 1

Answer:

the position R1= icap+2j cap-kcap ) to position r2=5i cap +4j cap+3kcap.the total work done by forces is

please please please answer my question..I will follow u

Explanation:

I I always answer will be help for you please like and follow me