Physics, asked by aarti67, 1 year ago

A particle is at x + 5 metre at =zero X = -7 m at t = 6 seconds and X = + 2 metre and T = 10 second. The average velocity of the particle during the interval (a) t = 0 to t= 6 second (b) t = 6 second to t = 10 second (c) t=10 second is
1) -2, 22.5, -0.3
2) 2, -22.5, 0.3
3) 0.3, 2 , -22.5
4) 2.25, -0.3, -2

Answers

Answered by anujadiwakar67
2

Secondary SchoolPhysics 5+3 pts



A particle moves along a straight line with a constant acceleration a =+0.5m/s^2.At t=0 it is at x=0 and its velocity is v=0.plot the velocity-time and position time graphs for the period t =0 to t=5 seconds


Report by Mahasweta14 15.05.2018

Answers


dragonard

Dragonard Helping Hand

this is the answer its free-hand draw with scale.


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4 votes

Comments (1) Report

dragonard

and for the second part of the question the graph would be a open parabola along y-axis where the distance value is plotted.

Shubhendu8898

Shubhendu8898 Brainly Legend

According to question the data which are given is a = 0.5 m/s2, u =0 at t =0 ,

hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)

using equation of motion

v = u+at

v = 0+0.5 x5 = 2.5 m/s.

now the displacement at the end of 5 second is

s = ut +0.5 at2

s = 0+ 0.5 x 0.5 x 52

= 6.25 metre..




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.

.

.çhere the two above figures shows the the velocity and position time graph.

now the equation is given

x = 20+12t

at t =0 x = 20m and at t = 5 x = 20+12x5 = 20+60 =80m

hence initial displacement is 20m

and the slope = tanθ = x/t = 60/5 = 12,.

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graphs are attached respectively






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