A particle is at x + 5 metre at =zero X = -7 m at t = 6 seconds and X = + 2 metre and T = 10 second. The average velocity of the particle during the interval (a) t = 0 to t= 6 second (b) t = 6 second to t = 10 second (c) t=10 second is
1) -2, 22.5, -0.3
2) 2, -22.5, 0.3
3) 0.3, 2 , -22.5
4) 2.25, -0.3, -2
Answers
Secondary SchoolPhysics 5+3 pts
A particle moves along a straight line with a constant acceleration a =+0.5m/s^2.At t=0 it is at x=0 and its velocity is v=0.plot the velocity-time and position time graphs for the period t =0 to t=5 seconds
Report by Mahasweta14 15.05.2018
Answers
dragonard
Dragonard Helping Hand
this is the answer its free-hand draw with scale.
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dragonard
and for the second part of the question the graph would be a open parabola along y-axis where the distance value is plotted.
Shubhendu8898
Shubhendu8898 Brainly Legend
According to question the data which are given is a = 0.5 m/s2, u =0 at t =0 ,
hence at the end of 5 second the particle has some other velocity and it must have covered some distance or displacement (since the particle is going straight)
using equation of motion
v = u+at
v = 0+0.5 x5 = 2.5 m/s.
now the displacement at the end of 5 second is
s = ut +0.5 at2
s = 0+ 0.5 x 0.5 x 52
= 6.25 metre..
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.çhere the two above figures shows the the velocity and position time graph.
now the equation is given
x = 20+12t
at t =0 x = 20m and at t = 5 x = 20+12x5 = 20+60 =80m
hence initial displacement is 20m
and the slope = tanθ = x/t = 60/5 = 12,.
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graphs are attached respectively