A particle is describing the circular path of radius 20m in every 2second .The average angular speed of the particle during 4 second is?
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Answered by
3
Answer:
ω = 1.57 rad / s
Explanation:
r = 20 m & t = 2 s
v = r ω
ω = v / r = 2 π r / r t
ω = 2 x 3.14 / 4
ω = 1.57 rad / s
Answered by
3
Answer:your answer is here:v/r =W therefore.we have to find its linear velocity after 4 sec but vel is constant then after 4 sec vel remain same speed=d/t .total distance cover = 4pie×r velocity= 20pie therefore angular speed = 20pie/20= pie
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