A particle is displaced 6m towards east and then 8m towards north and finally 10m vertically upwards. Find out the displacement of the particle.
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Let its started point =A
the second point it reaches= B
such that AB=6m
now let third point be C and fourth D such that BC=8m
and CD=10m, such that BD= (8+10)m
=18m
now in ⏏️ABD apply pgt we get
AD sq.=AB sq.+BD sq.
AD sq.=6 sq.+ 18 sq.
AD sq.=360
AD= sq. root 360
AD=18.97 (approx.)
therefore displacement= 18.97m
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