Question

a particle is displaced from (2i-j+k) to another position (3i+2j-2k) under the action of a force (2i+j-k) the work done by force is

Answer 1

displacement of particle=
(3i+2j-2k)-(2i-j+k)i=i+3j-3k
work done=f.d
(2i+j-k).(i+3j-3k)=2+3+3=8joules

Answer 2

s = i+3j-3k
F = 2i+j-k

W = F.S
= 8 joule