Question

A particle is displaced from point A (0,0) to point B (4,2) along a parabolic path whose equation is = y = √x. What will be work done by a force = 2y2i + 3xſ when the particle is displace form point A y (0,0) to point B (4,2) along the parabolic path y = √x​

Answer 1

W=F.ΔS

W=F.ΔSΔS=(3−1)i^+(4−2)j^

W=F.ΔSΔS=(3−1)i^+(4−2)j^=(2i^+3j^).(2i^+2j^)=2×2+3×2=10units

W=F.ΔSΔS=(3−1)i^+(4−2)j^=(2i^+3j^).(2i^+2j^)=2×2+3×2=10unitsWas this answer helpful?

Answer 2

W= F.ΔS

ΔS=(3−1) i^ +(4−2) j^

=(2i^ +3 j^ ).(2 i^ +2j^ )

=2×2+3×2=10units

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