Question

. A particle is displaced from position 3i+2j meter to another position 14ỉ +13j meter by applying a force 4i+ j newton on it. Calculate the work done by the force. (a) 12j (b) 45J (c) 35j (d) 55J
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Answer 1

Answer:

• Total Displacement:

$\implies \tt\overrightarrow{ s}=\overrightarrow{ s_2} -\overrightarrow{s_1}$

$\implies\tt\overrightarrow{ s }=(14 \hat{i} + 13\hat{j} ) - (3\hat{i} + 2\hat{j} )$

$\implies\tt\overrightarrow{ s}=11 \hat{i} + 11\hat{j}$

Work done:

$\implies \sf Work \: Done = F.s$

$\implies \sf Work \: Done = (4 \hat{i} + 1 \hat{j}).(11 \hat{i} + 11 \hat{j})$

$\implies \sf Work \: Done =44 + 11$

$\implies \red{\underline{\underline{ \orange{\textsf{\textbf{Work Done = 55 J}}}}}}$

Hence, the Option D) 55 J is the correct answer.