A particle is displaced over S=i+ 2j - 4 k m due to force of f = 2i + 3j -6k Newton find the work done
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We know that,
Work Done = F*s
|S| = √1²+2²+(-4)² = √21
|F| = √2²+3²+(-6)² = √49 = 7
Therefore, W.D = F*S = √21*7 = 7√21 N-m
Hope it Helps!
Work Done = F*s
|S| = √1²+2²+(-4)² = √21
|F| = √2²+3²+(-6)² = √49 = 7
Therefore, W.D = F*S = √21*7 = 7√21 N-m
Hope it Helps!
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